I. x3 = 1728
II. y2 – 15y + 56 = 0
I. x3 = 1728 => x = 12 II. y2 – 15y + 56 = 0 => y2 – 7y – 8y + 56 = 0 => y(y – 7) – 8(y – 7) = 0 => (y – 7) (y – 8) = 0 => y = 7, 8 Hence, x > y.
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...1053 ÷ 27 + 17 × 9 = ?
10% of 100 + 14 = ?% of 120
√10000 × √8100 - (50)² = √(?) + (80)²
1156 ÷ 17 × 5 – 156 = (8)?
(25 + 12) x 6 + 34 = ? + 18
215 + 378 – 23 + 15 - 27 = ? + 3² + 16²
1404 ÷ 26 x 3 + 7 = ?2
40% of (362 ÷ 0.05) = ?
17.8 + 3/7 of 89.6 = ?