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    Question

    I. 64x2 - 64x + 15  = 0      II.

    21y2 - 13y + 2  =0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer if 
    A If x = y or relationship between x and y cannot be established. Correct Answer Incorrect Answer
    B If x > y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≥ y Correct Answer Incorrect Answer
    E If x ≤ y Correct Answer Incorrect Answer

    Solution

    I. 64x2 - 64x + 15  = 0 64x2 - 24x - 40x + 15 = 0 8x (8x - 3 ) - 5 ( 8x - 3 ) = 0    (8x - 5 ) ( 8x - 3) = 0 x = (3/8), (5/8) II. 21y2 - 13y + 2  =0 21y2 - 7y - 6y + 2 = 0 7y ( 3y - 1 ) -2 ( 3y - 1 ) = 0 y = (2/7), (1/3) Hence, x > y.

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