Question
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â II.
21y2 - 13y + 2Â =0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer ifÂSolution
I. 64x2Â - 64x + 15 Â = 0 64x2Â - 24x - 40x + 15 = 0 8x (8x - 3 ) - 5 ( 8x - 3 ) = 0Â Â (8x - 5 ) ( 8x - 3) = 0 x = (3/8), (5/8) II. 21y2 - 13y + 2 Â =0 21y2 - 7y - 6y + 2 = 0 7y ( 3y - 1 ) -2 ( 3y - 1 ) = 0 y = (2/7), (1/3) Hence, x > y.
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