Question
I. 2x2 + 5x + 2 = 0 II. 4y2
= 1Solution
I. 2x2 + 5x + 2 = 0 2x2 + 4x + x + 2 = 0 2x(x + 2) + 1(x + 2) = 0 (2x + 1) (x + 2) = 0 x = - 1/2 , - 2 II. 4y² = 1 y² = 1/4 y = ± 1/2 Hence, x ≤ y
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