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    Question

    Solve the quadratic equations and determine the relation

    between x and y: Equation 1: x² - 26x + 168 = 0 Equation 2: y² - 23y + 132 = 0
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From Equation 1: x² - 26x + 168 = 0 Factorizing: (x - 12)(x - 14) = 0 So, x = 12 or x = 14. From Equation 2: y² - 23y + 132 = 0 Factorizing: (y - 11)(y - 12) = 0 So, y = 11 or y = 12. Comparing x and y: x = 12, y = 11 → x > y x = 12, y = 12 → x = y x = 14, y = 11 → x > y x = 14, y = 12 → x > y Correct option: B) x ≥ y

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