I. x2 – 7x + 12 = 0
II. y2 – 7y + 10 = 0
I. x2 – 7x + 12 = 0 => x2 – 4x – 3x + 12 = 0 => x(x – 4) – 3(x – 4) = 0 => (x – 4) (x – 3) = 0 => x = 4, 3 II. y2 – 7y + 10 = 0 => y2 – 5y – 2y + 10 = 0 => y(y – 5) – 2(y – 5) = 0 => (y – 5) (y – 2) = 0 => y = 5, 2 Hence, relation cannot be established. Alternate Method: if signs of quadratic equation is -ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 4, 3 So, roots of second equation = y = 5, 2 After comparing we can conclude that relationship cannot be established between x and y.
In which of these expression ‘N > G’ is definitely True?
Statement:A≤T<B =C ≤P<D;D>J ≥S
I. C >S
II. J < D
Statements:
X = P < M = T > K; S > L ≥ M > O
Conclusions:
I). T > O
II). S > X
Which of the following symbols should replace the sign (@) respectively in the given expression in order to make the expression P ≥ O and D > K defin...
Statement:M = C ≥ A = V < Q = S
Conclusions:
I. M ≥ V
II. A < S
Statement: A ≤ B; A ≤ I; B = D; I < C
Conclusion:
I. C ≤ B
II. D ≥ C
Statements: Â SÂ * Â C, C $ T, T # U, U % VÂ Â
Conclusions :
I.V # T
II. C % U
III. S # U
IV. C % V...
Statements: D = B ≤ I < L ≥ M = R; T = U ≥ L
Conclusion: I. D < U II. B = T
Statements:Â Â Â Â Â Â Â A # B # O $ P & Q % R % Z
Conclusions :Â Â Â Â Â I. Q @ ZÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. Q & ZÂ Â Â Â Â Â Â Â Â Â Â...
Statements: G > H = M; N < R = H; S > R
Conclusions:
I. S > M
II. G < S
III. N > G
