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I. 10x2 + 33x + 9 = 0 => 10x2 + 30x + 3x + 9 = 0 =>10x(x + 3) + 3(x + 3) = 0 => (x + 3) (10x + 3) = 0 => x = -3, -3/10 II. 2y2 + 13y + 21 = 0 =>2y2 + 7y + 6y + 21 = 0 => y(2y + 7) + 3(2y + 7) = 0 => (2y + 7) (y + 3) = 0 => y = -7/2, -3 Hence, x ≥ y. Alternate Method: if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve. So, roots of first equation = x = -3, -3/10 So, roots of second equation = y = -7/2, -3 After comparing we can conclude that x ≥ y.
(804/65) ÷ (11/798) × (129/131) = ?
1560.182 ÷ √168 + √143 * √224 – 4649.87 ÷ 30.883= ?
15.35 x (58.25 + 63.98) = ? + 1029.78
√1600.13 x √4355.99 ÷ 329.98 + 1223.23 = ?
210.34 + 16.92² + ?³ = √900.56 * 31.23
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
In a cyclic quadrilateral ABCD, angle A = 70 degrees and angle B = 100 degrees. What is the measure of angle C?
60.22 of 449.98% + 459.99 ÷ 23.18 = ?
35.1% of 1599 = ?–(449.96 ÷ 6.12) × 2