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Distance in first condition = speed × time = 4y Distance in second condition = speed × time = (y+1) × 3 = 3x+3 4y = 3y+3 y = 3 distance = 3y+3 = 12 km time taken = 12/2 = 6 hour
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
13.232 + 19.98% of 549.99 = ? × 8.99
(7.992/√?) + √16/? = 14.032/?
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
(34.98% of 619.86 + 25.12% of 132.26) ÷ 14.86 × 23.98 = ? × 25.12
`sqrt623.798` × 24.034 +`sqrt403.898` × 17.907 =?
16.11 × 9.96 – (238.19 – 64.04 × 2.18) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
19.912 - (599.98 - 96.01 ÷ 3.01) ÷ 1.98 = ? + √254