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I. 6x2 + 19x + 10 = 0 => 6x2 + 15x + 4x + 10 = 0 =>3x(2x + 5) + 2(2x + 5) = 0 => (2x + 5) (3x + 2) = 0 => x = -5/2, -2/3 II. y2 + 10y + 25 = 0 =>y2 + 5y + 5y + 25 = 0 => y(y + 5) + 5(y + 5) = 0 => (y + 5) (y + 5) = 0 => y = -5, -5 Hence, x > y Alternate Method: if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve. So, roots of first equation = x = -5/2, -2/3 So, roots of second equation = y = -5, -5 After comparing we can conclude that x > y.
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