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    Question

    I. x2 + 91 = 20x II. 10y2 -

    29y + 21 = 0 In the following question two equations are given in variables x and y. You have to solve these equations and determine the relation between x and y.
    A If x > y Correct Answer Incorrect Answer
    B If x < y Correct Answer Incorrect Answer
    C If x ≥ y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E x = y or relation cannot be established between x and y Correct Answer Incorrect Answer

    Solution

    I. x2 + 91 = 20x => x2 - 20x + 91 = 0 => x2 - 13x - 7x + 91 = 0 =>x(x - 13) - 7(x - 13) = 0 => (x - 13) (x - 7) = 0 => x = 13, 7 II. 10y2 - 29y + 21 = 0 => 10y2 - 14y - 15y + 21 = 0 => 2y(5y - 7) - 3(5y - 7) = 0 => (5y - 7) (2y - 3) = 0 => y = 7/5, 3/2 Hence, x > y. Alternate Method: if signs of quadratic equation is - ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 13, 7 So, roots of second equation = y = 7/5, 3/2 After comparing we can conclude that x > y.

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