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    Question

    I. x²  – 44x + 468 = 0 II. y²  – 30y +

    216 = 0
    A x > y Correct Answer Incorrect Answer
    B x < y Correct Answer Incorrect Answer
    C x = y or the relationship cannot be established Correct Answer Incorrect Answer
    D x ≥ y Correct Answer Incorrect Answer
    E x ≤ y Correct Answer Incorrect Answer

    Solution

    From I: x2 – 44x + 468 = 0 Or, x2 – 18x – 26x + 468 = 0 Or, x × (x – 18) – 26 × (x – 18) = 0 Or, (x – 18) × (x – 26) = 0 So, x = 18 or, x = 26 From II: y2 – 30y + 216 = 0 Or, y2 – 12y – 18y + 216 = 0 Or, y × (y – 12) – 18 × (y – 12) = 0 Or, (y – 12) × (y – 18) = 0 So, y = 12 or y = 18 So, x ≥ y. Correct option: d

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