Question
I. 2x² + 11 x + 15 = 0   II. 2y² - 19 yÂ
+ 44 = 0Â Â Â In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 2x² + 11 x + 15 = 0   2x² + 6x + 5x + 15 = 0   2x (x + 3) + 5(x + 3) (2x + 5) (x + 3) x = - 5/2, - 3 II. 2y² - 19 y + 44 = 0   2y² - 11y - 8y - 44 = 0   y (2y – 11) – 4 (2 y – 11 ) (y – 4) (2y – 11) x = 4, 11/2 Hence, x < y.
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