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    Question

    I. 2x² + 11 x + 15 = 0     II. 2y² - 19 y 

    + 44 = 0     In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x ≥ y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x > y Correct Answer Incorrect Answer
    D If x < y Correct Answer Incorrect Answer

    Solution

    I. 2x² + 11 x + 15 = 0     2x² + 6x + 5x + 15 = 0     2x (x + 3) + 5(x  + 3) (2x + 5) (x  + 3) x = - 5/2,  - 3  II. 2y² - 19 y  + 44 = 0      2y² - 11y - 8y - 44 = 0     y (2y – 11) – 4 (2 y – 11 ) (y – 4) (2y – 11) x =  4, 11/2 Hence, x < y.

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