I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. x2– 10x + 21 =0 => x2- 7x - 3x + 21 = 0 => x(x - 7) - 3(x - 7) = 0 => (x - 7) (x - 3) = 0 => x = 7, 3 II. y2+ 11y + 28 =0 => y2+ 7y + 4y + 28 = 0 => y(y + 7) + 4(y + 7) = 0 => (y + 7) (y + 4) = 0 => y = -7, -4 Hence, x > y.
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