Question
I. 27x² + 120x + 77 = 0 II. 56y² + 117y
+ 36 = 0Solution
I. 27x² + 120x + 77 = 0 27x² + 21x + 99x + 77 = 0 3x(9x + 7) + 11(9x + 7) = 0 (9x + 7) (3x + 11) = 0 ∴ x = -7/9 , -11/3 II. 56y² + 117y + 36 = 0 56y² + 96y + 21y + 36 = 0 8y(7 y + 12) + 3(7 y + 12) = 0 (8 y + 3) (7 y + 12) = 0 ∴ y = -3/8 , -12/7 Hence, no relationship cannot be established between x and y.
If a + b + c = 6, a³ + b³ + c³-3abc = 342, then what is the value of ab + bc + ca
If (a + b) = 10 and ab = 21, find the value of (a² + b²).
You are provided with three sequences below. Determine the values of P, Q, and R, and then identify the relationship among them.<...
= ? If ( p = 60 - q - r ) and ( pq + r(q + p) = 1080), then find the value of ( p2 + q2 + r2).
If (x 2 = 6x – 9), then find the value of [x³ + (x⁴/9)][5 - x³]
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf tan x + cot x = 7, find tan3 x + cot3 x = ?
If x + y = 10 and xy = 21, find value of x³ + y³.
If (a3+1)/(a+1) = (a3-1)/(a-1) and a ≠ 1, -1. Find the value of 'a'
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