Question
I. 27x² + 120x + 77 = 0 II. 56y² + 117y
+ 36 = 0Solution
I. 27x² + 120x + 77 = 0 27x² + 21x + 99x + 77 = 0 3x(9x + 7) + 11(9x + 7) = 0 (9x + 7) (3x + 11) = 0 ∴ x = -7/9 , -11/3 II. 56y² + 117y + 36 = 0 56y² + 96y + 21y + 36 = 0 8y(7 y + 12) + 3(7 y + 12) = 0 (8 y + 3) (7 y + 12) = 0 ∴ y = -3/8 , -12/7 Hence, no relationship cannot be established between x and y.
The LCM and the HCF of the numbers 30 and 45 are in the ratio:
Determine the HCF of 150 and 1350.
The LCM of two numbers is 40 times its HCF. If the product of the numbers is 1440, find their HCF.
The LCM of two numbers is 33 times of their HCF. The sum of the LCM and HCF is 850. If one number is 25, then the other number is:
Find the LCM of the numbers 1.2, 0.8, 2.4, and 3.6.
What is the difference between the LCM and HCF of 36, 40?
- The LCM and HCF of two integers are 540 and 12 respectively. If one of the integers is 90, find the second integer.
The LCM of two numbers is 168, and the numbers are in the ratio 4:7. Find the sum of the numbers.
The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 320. If one of the number is 256, then the other number is:
