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    Question

    I. 6x² - 13 x + 6 = 0 II. 15 y² + 11 y

    - 12 = 0
    A If x ≥ y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x > y Correct Answer Incorrect Answer
    D If x < y Correct Answer Incorrect Answer
    E If relationship between a and b cannot be established or x = y Correct Answer Incorrect Answer

    Solution

    I. 6x² - 13 x + 6 = 0 6x² - 4 x - 9 x + 6 = 0 2 x (3 x – 2) – 3 (3 x – 2) = 0 (2 x – 3) (3 x – 2) = 0 x = 2/3 , 3/2 II. 15 y² + 11 y - 12 = 0 15 y² - 9 y + 20 y - 12 = 0 3 y (5 y – 3) + 4(5 y – 3) = 0 (3y + 4) (5 y – 3) = 0 y = -4/3 , 3/5 Hence, x > y

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