Question
I. 6x² - 13 x + 6 = 0 II. 15 y² + 11 y
- 12 = 0Solution
I. 6x² - 13 x + 6 = 0 6x² - 4 x - 9 x + 6 = 0 2 x (3 x – 2) – 3 (3 x – 2) = 0 (2 x – 3) (3 x – 2) = 0 x = 2/3 , 3/2 II. 15 y² + 11 y - 12 = 0 15 y² - 9 y + 20 y - 12 = 0 3 y (5 y – 3) + 4(5 y – 3) = 0 (3y + 4) (5 y – 3) = 0 y = -4/3 , 3/5 Hence, x > y
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
