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    Question

    I. 6 y² + 11 y – 7= 0 II. 21 x² + 5 x – 6 =

    0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x>y Correct Answer Incorrect Answer
    B if x≥y Correct Answer Incorrect Answer
    C if x Correct Answer Incorrect Answer
    D if x ≤y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 6 y² + 11 y – 7= 0 6 y² + 14 y - 3 y– 7= 0  2 y(3 y + 7) – 1(3 y + 7) = 0 (2 y – 1)(3 y + 7) = 0 y = 1/2,- 7/3  II. 21 x² + 5 x – 6 = 0 21 x² + 14 x - 9 x – 6 = 0  7 x(3 x + 2) – 3(3 x + 2) = 0  (7 x – 3)(3 x + 2) = 0 x = 3/7, -2/3  Hence, relationship cannot be established between x and y

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