Question
If the numerator of a fraction is increased by 40% and
the denominator is decreased by 20%, then the value of the fraction becomes 21/16. Then tell the value of the original fractionSolution
Let the friction be a/b   Then –      a/b×140/80  =  21/16  a/b×7/4  = 21/16  a/b  = 3/4
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