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    Question

    If the numerator of a fraction is increased by 40% and

    the denominator is decreased by 20%, then the value of the fraction becomes 21/16. Then tell the value of the original fraction
    A 3/4 Correct Answer Incorrect Answer
    B 5/4 Correct Answer Incorrect Answer
    C 4/3 Correct Answer Incorrect Answer
    D 4/5 Correct Answer Incorrect Answer

    Solution

    Let the friction be a/b     Then –            a/b×140/80   =   21/16   a/b×7/4    =  21/16   a/b   = 3/4

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