Question
What is least number which when successively divided by
6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?Solution
ATQ,
First condition: Nβ‘5(mod6). Let N=6a+5. Second condition: Quotient aβ‘3(mod4). Let a=4b+3. Substituting: N=6(4b+3)+5=24b+18+5=24b+23. Third condition: Quotient bβ‘3(mod4). Let b=4c+3. Substituting: N=24(4c+3)+23=96c+72+23=96c+95. Smallest N: Set c=0: N=96(0)+95=95. The least N is 95.
What value should come in place of (?) in the given expression.
450 Γ· 9 + 75% of 160 β 64 Γ· 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 Γ 9 Γ· 12 + 162 ] Γ· 4 = ?
What should come in place of (?) question mark in the given expression.
Β (25% of 320) + (3/8 of 400) β 30 = ?
45% of 360 - 160 + ? = β324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 Γ 4 Γ· 2 Γ· 2) Γ 5 β 8} + 13 of 8]
18 Γ 15 + 86 β 58 =? + 38
Β
√(24²+285-8²-172) = ?²