Question
Meera buys a laptop and sells it to Sneha at a profit of
25%. Sneha then sells it to Tushar at a loss of 10%. If Tushar buys the laptop for Rs. 36,450, find the price at which Sneha bought the laptop.Solution
ATQ, Let the cost price of the laptop for Meera be Rs. '100y'. Cost price of the laptop for Sneha = 1.25 × 100y = Rs. '125y' Cost price of the laptop for Tushar = 125y × 0.90 = Rs. '112.5y' ATQ, 112.5y = 36,450 So, y = (36450/112.5) = 324 Therefore, the price at which Sneha bought the laptop = 125y = 125 × 324 = Rs.40,500.
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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