Question
The sum to n terms of the series 1 + 1 + 3 + 1 + 3 + 5 +
1 + 3 + 5 + 7 …………………… isSolution
1 + (1 + 3) + (1 + 3 + 5) +..... = this will be something like : 1 + 4 + 9 + 16 + 25 + 36.... .... (ie. the sum of squares of natural numbers)
and the sum of squares of n terms can be given by : n(n+1)(2n+1)/6
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