Question
The sum to n terms of the series 1 + 1 + 3 + 1 + 3 + 5 +
1 + 3 + 5 + 7 …………………… isSolution
1 + (1 + 3) + (1 + 3 + 5) +..... = this will be something like : 1 + 4 + 9 + 16 + 25 + 36.... .... (ie. the sum of squares of natural numbers)
and the sum of squares of n terms can be given by : n(n+1)(2n+1)/6
12.99% of 499.99 ÷ 13.17 = ? ÷ 20.15
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
124.80 + 50.01 + √170 = ? ÷ 5
29.81 % of 49.91 + 14.28% of 147.09 + 179.91 = ?3
44.89% of 1199.78 + 319.68 = ? × 42.79
(100.01% of 44.89) ÷ 14.98 = √? - √48.98
? + 96.18 – 15.02 = 118.98 + 31.09
37.5% of [34.99 ÷ (21.07/5.98) of 7.99 ÷ 2.18] = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...45.1298% of (14.032 - 75.98) + 27.87% of √40001 = 449.98% of 24.098 + ?