Question
A total of Rs. 558 was distributed among P, Q, R, S, T,
and U. The amounts they received were in descending order and formed an arithmetic progression. S received Rs. 36 less than P. What was the combined amount received by Q and U?Solution
Let the sums received by P, Q, R, S, T and U are a+5d, a+4d, a+3d, a+2d, a+d and a respectively a+5d + a+4d + a+3d + a+2d + a+d + a = 558 6a+15d = 558 0r 2a+5d = 186 And also, (a+5d) – (a+2d) = 36 3d = 36 d = 12 now from 2a+5d = 186 we get a = 63 sum of Q = a+4d sum of U = a sum of Q and U = a+a+4d = 174
Find the wrong number in the given number series.
4, 7, 12, 19, 30, 43, 61
4Â Â Â Â Â 6Â Â Â Â Â Â 12Â Â Â Â Â 30 Â Â Â Â Â Â 90 Â Â Â Â Â Â Â 310
...Find the wrong number in the given series.
46, 104, 184, 404, 760, 1586
- Find the wrong number in the given number series.
118, 150, 178, 206, 238, 266 21, 44, 78, 121, 179, 246
Find the wrong number in the given number series.
30, 26, 24, 18, 14, 10
Find the odd one out in the following series:
159, 240, 256, 292, 373, 420
4, 8, 24, 96, 485, 2880, 20160
Find the wrong number in the given number series.
45,  54, 79, 128, 189,  330,  499
75, 450, 225, 1330, 675, 4050
Relevant for Exams:
