Question
The sum of three numbers in AP is 21, and their product
is 315. Find the numbers.Solution
ATQ,
→ Let (a − d), a, (a + d). Sum = 3a = 21 ⇒ a = 7. Product = (7 − d)·7·(7 + d) = 315 ⇒ 7(49 − d²) = 315 ⇒ 49 − d² = 45 ⇒ d² = 4 ⇒ d = 2. Numbers: 5, 7, 9
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