Question
If p = q + 2, where q is the product of six consecutive
positive integers, then which of the following is/are true? a. p is a perfect cube b. p is a multiple of 6 c. p is oddSolution
Let q = [x (x + 1) (x + 2) (x + 3) (x + 4) (x + 5)] If x= 2 Then q= 1 x 2 x 3 x 4 x 5 x 6 = 720 Then p = 722 Here p is an even number.
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