Question
Sum of first 20 terms of an AP is 610. First term = 12.
Find approximate common difference.Solution
ATQ, → S = (n/2)[2a + (n–1)d] → 610 = 10(24 + 19d) → d = 37/19 ≈ 1.95 or 2
Answer the questions based on the information given below.
A & B means A is greater than B
A * B means A is not greater than B
A ...
Statements: M % N, N & A, A @ B, B # C
Conclusions: I. C & AÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M # B
...Statements: R > S > T ≥ U; Q ≥ R; W = V < U
Conclusions:
I. S > Q
II. W < T
III. Q > W
In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and ...
Statements:
N < P ≤ I = O; P ≥ J ≥ K ≥ W; Z ≤ M ≤ W
Conclusions:
I) O > Z
II) O = Z
...Statements: M $ K; K & N, N % R, R @ W
Conclusions:Â Â Â Â Â
I. W & KÂ Â Â Â Â Â Â Â
II. K & WÂ Â Â Â Â Â Â Â Â Â Â Â ...
Statements: I ≥ E = S > J < N > V > Q ≤ O
Conclusion
I: I > S
II: Q < N
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statements: F > V > W ≥ L > G; F ≤ O = M < I
Conclusions: I. M > LÂ Â Â II. V < I
