Question

    Present average age of A, B and C together is 44 years.

    Age of B is 12 Years hence from now will be 260% more than age of A. Four years ago from now while age of C after 12 years hence from now will be 50% more than the age of B 20 years ago from now. 4 years hence from now, what will be the ratio of ages of A and C? Desire difference.
    A 3:5 Correct Answer Incorrect Answer
    B 4:7 Correct Answer Incorrect Answer
    C 5:8 Correct Answer Incorrect Answer
    D 7:13 Correct Answer Incorrect Answer
    E 9:17 Correct Answer Incorrect Answer

    Solution

    Let present age of A, B and C is a, b, and c respectively So a+b+c = 44*3= 132--------(1) And, (b+12) = 3.6*(a-4) 5b+60 = 18(a-4) 18a-5b=132---------(2) And, (c+12) = 1.5*(b-20) 3b-2c=84---------(3) Solving equation 1, 2 and 3 we get a=24, b = 60, and c = 48 Age of A, B 4 years hence now will be 28 and 52 respectively. Required ratio = 28:52 = 7:13

    Practice Next
    More Arithmetic Progression Questions

    Relevant for Exams:

    ask-question