If x + (1/x) = 3, then x2 + (1/x2) will be –
x + (1/x) = 3 ⇒ (x + 1/x) ² = (3)² ⇒ x2 + 1/x2+ 2 = 9 ∴ x2 + 1/x2 + 2 = 9 – 2 = 7
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