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Start learning 50% faster. Sign in nowGiven – a= 701, b=703, c = 706 Then as we know that a³ + b³ +c³ –3abc = (a +b + c)/2 [(a-b) ² +(b-c) ² +(c-a) ²] = (701+703+706)/2 [4+9+25] =2110 / 2 [38] =2110×19= 40090
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Identify the element with an electronic configuration 2,8,1 from among the following options.
