Question
If a = 701, b= 703 and c= 706, then find the value of
aĀ³ + bĀ³ +cĀ³ ā3abc?Solution
Given ā a= 701, b=703, c = 706 Then as we know that aĀ³ + bĀ³ +cĀ³ ā3abc = (a +b + c)/2 [(a-b) Ā² +(b-c) Ā² +(c-a) Ā²] = (701+703+706)/2 [4+9+25] =2110 / 2 [38] =2110Ć19= 40090
' pqr ktp ' is code for?Ā
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