Question
If (10 a³ + 4b³): (11a³ — 15b³) = 7:5, then (3a +
5b): (9a - 2b) = ?Solution
10a3 + 4b3 /11a3 – 15b3 = 7/5 =50a3 +20b3 = 77a3 -105b3 = 27a3 = 125b3 = a3 / b3 = 125/27 = a/b = 5/3 = (3a + 5b) / (9a – 2b) = 3 × 5 + 5 × 3 / 9 × 5 – 2 × 6 = 30/39 = 10 : 13
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