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    Question

    If a = 32, b = c = 31, then find the value of a

    3  + b 3  + c 3  – 3abc.
    A 94 Correct Answer Incorrect Answer
    B 102 Correct Answer Incorrect Answer
    C 66 Correct Answer Incorrect Answer
    D None of the above Correct Answer Incorrect Answer

    Solution

    We know, a 3  + b 3  + c 3  – 3abc = (a + b+ c){(a – b) 2  + (b – c) 2  + (c – a) 2 }/2

    Or, a 3  + b 3  + c 3  – 3abc = (32 + 31 + 31){(32 – 31) 2  + (31 – 31) 2  + (31 – 32) 2 }/2 = 94 × (2/2) = 94

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