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      Question

      If a = 32, b = c = 31, then find the value of a

      3  + b 3  + c 3  – 3abc.
      A 94 Correct Answer Incorrect Answer
      B 102 Correct Answer Incorrect Answer
      C 66 Correct Answer Incorrect Answer
      D None of the above Correct Answer Incorrect Answer

      Solution

      We know, a 3  + b 3  + c 3  – 3abc = (a + b+ c){(a – b) 2  + (b – c) 2  + (c – a) 2 }/2

      Or, a 3  + b 3  + c 3  – 3abc = (32 + 31 + 31){(32 – 31) 2  + (31 – 31) 2  + (31 – 32) 2 }/2 = 94 × (2/2) = 94

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