Question
If (a + b) = 11 and (a2 + b2) = 65, then find the value of (a × b).
Solution
(a + b) = 11 Squaring on both sides, we get, a2 + b2 + 2ab = 121 Or, 65 + 2ab = 121 Or, 2ab = 121 – 65 = 56 Or, ab = 56/2 = 28
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