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    Question

    if a2 + b2 +

    c2┬а=┬а2(4a -5b -9c)-122 , then a-b-c = ?
    A 14 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 18 Correct Answer Incorrect Answer
    D 11 Correct Answer Incorrect Answer

    Solution

    a2 + b2 + c2 =┬а2(4a -5b -9c)-122 So a2┬а+ b2┬а+ c2┬а-2├Ч4a +2 ├Ч5b + 2├Ч9c +122 = 0 a2┬а-2├Ч4a +16 + b2 +2 ├Ч5b+25 +c2 +2├Ч9c+81 = 0 So (a-4)2 +(b+5)2+(c+9)2 = 0 As we know that if x2 + y2 +z2 = 0 then x=y=z = 0 So here a-4 = 0 so a =4; b +5 = 0 so b = -5 And c+9 =0 so c = -9 So now a-b-c = 4-(-5)-(-9) = 4+5+9 = 18

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