Question
Train ‘A’ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 130.5 × (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 × 48 => 5x = 1740 => x = 348 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(348 + 60)/(48 + 20)} = 6 seconds
More Trains Questions
What will come in the place of question mark (?) in the given expression?
133 ÷ 19 X √576 + ? ÷ 2 = 32 X 7.525% of 250 + 32% of 200 = ? ÷ √ 16
Find the value of ‘a’ in the following expression:
12 × a × 24 ÷ 8 + 72 – 46 = 170
447.8 × 441.2 ÷ 445 = 44 × 44?
- What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 
-Constable/1722079503-23.JPG)
15% of 1800 + 22 = ?
13/3 – (23/6) = ? – (22/9)
(20% of 15% of 600 – 6) × 5 + 84 = ?2
