Question
Train βAβ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 20 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 130.5 Γ (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 Γ 48 => 5x = 1740 => x = 348 Therefore, time taken by train βBβ to cross train βAβ = {(348 + 60)/(48 + 20)} = 6 seconds
What will come in the place of question mark (?) in the given expression?
133 Γ· 19 X β576 + ? Γ· 2 = 32 X 7.525% of 250 + 32% of 200 = ? Γ· β 16
Find the value of βaβ in the following expression:
12 Γ a Γ 24 Γ· 8 + 72 β 46 = 170
447.8 × 441.2 ÷ 445 = 44 × 44?
- What will come in the place of question mark (?) in the given expression?
(β1089 + 47) X 4.5 = ? - β256 X 10 15% of 1800 + 22 = ?Β
13/3 β (23/6) = ? β (22/9)
(20% of 15% of 600 β 6) Γ 5 + 84 = ?2Β