Question
Train ‘A’ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 130.5 × (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 × 48 => 5x = 1740 => x = 348 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(348 + 60)/(48 + 20)} = 6 seconds
More Trains Questions
36% of 250 + 26 ÷ 2 × ? = 207
{(700 ÷ 20) × 40} – 30 × 18 = ?% of 1000
72 x 60 x 22 x 32 =?
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
37% of 810 – 32% of 460.5 = ?
166/? = √576 - 3.25
?% of 320 - 69 = 123
212 + 14 × 23 – 28 × 15 = ?
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
What will come in the place of question mark (?) in the given expression?
(243/9) X 5 - 112 = ? ÷ (24 - 13)
