Question
Train ‘A’ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 130.5 × (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 × 48 => 5x = 1740 => x = 348 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(348 + 60)/(48 + 20)} = 6 seconds
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