Question
Train βAβ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 20 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 130.5 Γ (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 Γ 48 => 5x = 1740 => x = 348 Therefore, time taken by train βBβ to cross train βAβ = {(348 + 60)/(48 + 20)} = 6 seconds
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