Question
Train ‘A’ running with a speed of 130.5 km/hr can
cross a standing goods train of 4 times its length in 48 seconds. Find the time taken by 60 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 20 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 130.5 × (5/18) = 36.25 m/s According to the question, 4x + x = 36.25 × 48 => 5x = 1740 => x = 348 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(348 + 60)/(48 + 20)} = 6 seconds
What will come in place of the question mark (?) in the following series?
75, 219, 388, ?, 809, 106516.12 × 15.94 + 654.92 – 344.83 = ?× 5.95
660, 653, 639, 618, 590, ?
120, 126, 138, 162, ?, 306
11          20          ?             64          112        192
...Find the missing term in the series:
2, 5, 11, 23, 47, ?
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17, 38, 123, 508, ?, 15426
What will come in place of the question mark (?) in the following series?
55, 176, 320, ?, 685, 910
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