Question
A train has to cover a distance of 90 km in 15 hours. If
it covers half the journey in 4/5 th of the time, the speed to cover remaining distance in the time left has to beSolution
Total Distance = 90km Total Time = 15 hours 4/5th of the time = 15 × 4/5 = 12 hours Now, remaining distance = 90-45 = 45km Remaining time = 15 – 12 = 3 hours Average speed to cover the distance of 45 km will be 45/3 = 15km/hr.
The coefficient of ‘b2’ in (3a + b)3 is
[a/(2a²  + 5a + 2)] = 1/6 , then find the value of (a+1)/a ?
If (x24Â +Â 1)/x12Â = 7, then the value of (x72Â +Â 1)/x36Â isÂ
If x + 1/x = 3, find the value of x³ + 1/x³.
If x + y + xy = 118, such that x < y and both 'x' and 'y' are positive integers, then find minimum value of (x + y) .
If, ( a + b = 12 ) and ( a² + b² = 80 ), then find the value of (a³ + b³). Â
If (2a + b)/(3b - 2b) = 13/2 then 'b' is what percent of 'a'?
If (x2 + y2) = 9 and (xy)2 = 3, then find the value of (x4 + y4).
What is the average of the first 20 multiples of 12?
If a – b – c = 0, then the value of (a2 + b2 + c2)/(b + ac) is:
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