Question
Train 'A' is 200 meters long and takes 15 seconds to
cross a pole. The same train crosses train 'B' (which is 240 meters long) coming from the opposite direction in 19.8 seconds. Determine the speed of train 'B'.Solution
Speed of train βAβ = 200/15 = (40/3) m/sLet speed of train βBβ is βxβ m/sSo, (200 + 240)/(x + 40/3) = 19.8Or, x + 40/3 = 440/19.8 = 200/9Or, x = (200/9) β (40/3) = 80/9 m/sSpeed of train βBβ = (80/9) Γ (18/5) = 32 km/h
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