Question
Train 'A' is 200 meters long and takes 15 seconds to
cross a pole. The same train crosses train 'B' (which is 240 meters long) coming from the opposite direction in 19.8 seconds. Determine the speed of train 'B'.Solution
Speed of train ‘A’ = 200/15 = (40/3) m/sLet speed of train ‘B’ is ‘x’ m/sSo, (200 + 240)/(x + 40/3) = 19.8Or, x + 40/3 = 440/19.8 = 200/9Or, x = (200/9) – (40/3) = 80/9 m/sSpeed of train ‘B’ = (80/9) × (18/5) = 32 km/h
More Trains Questions
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 × 31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98
