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Speed of train ‘A’ = 200/15 = (40/3) m/sLet speed of train ‘B’ is ‘x’ m/sSo, (200 + 240)/(x + 40/3) = 19.8Or, x + 40/3 = 440/19.8 = 200/9Or, x = (200/9) – (40/3) = 80/9 m/sSpeed of train ‘B’ = (80/9) × (18/5) = 32 km/h
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............................... is a curve which shows various combinations of inputs that cost the same total amount .
