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Start learning 50% faster. Sign in nowLet the speed of 'A' be 'x' m/sec.
ATQ,
{(180 + 100) /x} = 14
(280/x) = 14
So, 'x' = 20
So, speed of 'B' = 20 X 1.25 = 25 m/sec
Length of train 'B' = 180 X (5/6) = 150 metres
Required time = (150 + 100) /25 = 10 seconds
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