Question
A train, 'A,' which is 180 meters long, takes 14 seconds to
cross a 100-meter-long bridge. If the lengths of trains 'A' and 'B' are in a ratio of 6:5, and train 'B' travels at a speed that is 25% faster than train 'A,' how much time will train 'B' take to cross the same bridge?Solution
Let the speed of 'A' be 'x' m/sec.
ATQ,
{(180 + 100) /x} = 14
(280/x) = 14
So, 'x' = 20
So, speed of 'B' = 20 X 1.25 = 25 m/sec
Length of train 'B' = 180 X (5/6) = 150 metres
Required time = (150 + 100) /25 = 10 seconds
More Trains Questions
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â
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