A 240 meters long Train A and y meters long Train B cross a pole in 12 seconds and 12 seconds respectively. If the speed of Train B is 50% more than that of Train A, then find the time taken by Train A to cross Train B when running in opposite directions?

Speed of Train A = 240 / 12 = 20 m/s ATQ, Speed of Train B = (1 + 50/100) * Speed of Train A Or, Speed of Train B = 1.5 * 20 So, Speed of Train B = 30 m/s Now, length of Train B (y) = Speed of Train B * 12 Or, y = 30 * 12 = 360 meters When both trains run in opposite directions, relative speed = Speed of Train A + Speed of Train B Or, Relative speed = 20 + 30 = 50 m/s Total distance to be covered = Length of Train A + Length of Train B Or, Total distance = 240 + 360 = 600 meters So, Time taken to cross each other = Total distance / Relative speed Or, Time taken = 600 / 50 = 12 seconds Hence, the correct answer is B.