Question
The speeds of train 'A' and 'B' are 20 m/s and 30 m/s,
respectively. Whereas the lengths of train 'A' and 'B' are in the ratio 4:6, respectively. If the trains take 5 seconds to cross each other while travelling in opposite directions, then find the length of train 'A'.Solution
Let the length of trains 'A' and 'B' be '4x' metres and '6x' metres, respectively. ATQ; {4x + 6x}/{20 + 30} = 5 {10x/50} = 5 10x = 250
x = 25
So, length of train 'A' = 4x = 4 × 25 = 100 metres
49.99% of 639.99 + 159.98% of 49.99 = ?2
(5.013 – 30.04) = ? + 11.98% of 4799.98
(51.99² - 19.05² )÷ ? = 14.11² - 140.33
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
What approximate value will replace the question mark (?) in the following?
29.99...
(18.21)² - (12.9)² = 20% of 649.9 - ? + 400.033
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
(11.75)2 - 49.99% of 120 - ? = (8.23)2Â