Question
A train 200 m long crosses a pole in 10 sec and a
platform in 25 sec. Find the platform’s length.Solution
ATQ,
Speed = 200/10 = 20 m/s Total distance for platform = 20Ă—25 = 500 m Platform length = 500 - 200 = 300 m
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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