Question
Shatabdi express leaves Delhi Junction at a certain
time. After 5 hours, Garib Rath leaves the same station and travels in the same direction at a speed of 100 km/hr. If Garib Rath catches up to Shatabdi in 15 hours, then what is the speed of Shatabdi express?Solution
ATQ Distance travelled by Garib Rath in 15 hours = 15 × 100 = 1500 km Speed of Shatabdi express = 1500/(15 + 5) = 1500/20 = 75 km/h
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√3598 × √(230 ) ÷ √102= ?
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4567.89 - 567.89 - 678.89 = ?
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18×4+96÷8=? ((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
9999² + 1111² =?
- What will come in the place of question mark (?) in the given expression?
(120 - ?) ÷ 2 + 35 = 86 - 11
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