Question
Length of Madhubani Express is (x + 40) m, and it can cross
a platform of length (x – 40) m in 40 seconds with a speed of 24 m/s. Find the time taken by Madhubani Express to cross another train of same length which is running at a speed of 28 m/s in the opposite direction towards it.Solution
Speed of Madhubani Express = [(x + 40) + (x – 40)]/40 m/s
According to question,
[(x + 40) + (x – 40)]/40 = 24
2x = 960, x = 960/2 = 480
So, length of Madhubani Express = 480 + 40 = 520 m
Therefore, required time = (520 + 520)/ (24 + 28) = 1040/52 = 20 seconds
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