Question
160 metre long train ‘A’ can cross a platform of
length 120 metres in 16 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(160 + 120)/16} = (280/16) = 17.5 m/s Speed of train ‘B’ = 17.5 + 6 = 23.5 m/s = 23.5 × (18/5) = 84.6 km/hr Required distance travelled by train ‘B’ = 84.6 × 5 = 423 km
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