Question
100 metre long train βAβ can cross a platform of
length 50 metres in 20 seconds. If the speed of train βBβ is 6 m/s more than that of train βAβ, then find the distance travelled by train βBβ in 5 hours.Solution
Speed of train βAβ = {(100 + 50)/20} = (150/20) = 7.5 m/s Speed of train βBβ = 7.5 + 6 = 13.5 m/s = 13.5 Γ (18/5) = 48.6 km/hr Required distance travelled by train βBβ = 48.6 Γ 5 = 243 km
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