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ATQ,
Let the length and speed of train be ‘l’ metres and ‘x’ m/s, respectively.
Then, according to question,
(l + 500)/30 = (l + 750)/40
40(l + 500) = 30(l + 750)
40l + 20000 = 30l + 22500
10l = 2500
l = 250 metres
x = (l + 500)/30 = 750/30 = 25 m/s = 25 × (18/5) = 90 km/h
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