Question
Two trains of equal lengths take 10 seconds and 15
seconds respectively to cross a telegraph post. If the length of each train be 240 metres, in what time will they cross each other travelling in opposite direction?Solution
Speed of the first train = [240/10] m/sec = 24 m/sec Speed of the second train = [240/15] m/sec = 16 m/sec Speed = (24 + 16) m/sec = 40 m/sec Required time = (480 + 480)/40 sec = 12 sec
More Trains Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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