Question
Train ‘A’ running with a speed of 108 km/hr
crosses a vertical pole in 16 seconds. Find the approx. time taken by the train ‘A’ to cross a train ‘B’ whose length is 130 metres less than that of train ‘A’ and whose speed is 1/3 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 108 × (5/18) = 30 m/sec
Length of train ‘A’ = 30 × 16 = 480 metres
Length of train ‘B’ = 480 – 130 = 350 metres
Speed of train ‘B’ = 30 + (30/3) = 40 m/sec
Required time taken = (480 + 350)/(30 + 40) = 11.85 = 12 seconds
More Trains Questions
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 
20% of 1500 – 75% of 200 = 125% of ?Â
5(? + 2)Â =Â 3125Â
7/3 of 4/5 of 15/56 of ? = 83
192.251 + 326.233 + 125.021 + 19.273 = ?
(165 × 12) ÷ 45 + 110 = ? × 2
Calculate the value of x2,  if [(8 + 62) ÷ 4 of x + 2.5 × 5 = 42 + 20% of 10].
14 × 11 + 25 – ? = 21% of 300
