Question
Train βAβ running with a speed of 108 km/hr crosses
a vertical pole in 6 seconds. Find the approx. time taken by the train βAβ to cross a train βBβ whose length is 120 metres less than that of train βAβ and whose speed is 1/10 more than that of train βAβ if both are running in opposite direction.Solution
Speed of train βAβ = 108 Γ (5/18) = 30 m/sec Length of train βAβ = 30 Γ 6 = 180 metres Length of train βBβ = 180 β 120 = 60 metres Speed of train βBβ = 30 + (30/10) = 33 m/sec Required time taken = (180 + 60)/(30 + 33) = 3.80 = 4 seconds
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