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      Question

      Train β€˜A’ running with a speed of 108 km/hr crosses

      a vertical pole in 6 seconds. Find the approx. time taken by the train β€˜A’ to cross a train β€˜B’ whose length is 120 metres less than that of train β€˜A’ and whose speed is 1/10 more than that of train β€˜A’ if both are running in opposite direction.
      A 8 seconds Correct Answer Incorrect Answer
      B 9 seconds Correct Answer Incorrect Answer
      C 4 seconds Correct Answer Incorrect Answer
      D 12 seconds Correct Answer Incorrect Answer

      Solution

      Speed of train β€˜A’ = 108 Γ— (5/18) = 30 m/sec Length of train β€˜A’ = 30 Γ— 6 = 180 metres Length of train β€˜B’ = 180 – 120 = 60 metres Speed of train β€˜B’ = 30 + (30/10) = 33 m/sec Required time taken = (180 + 60)/(30 + 33) = 3.80 = 4 seconds

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