Question
Two cars start from a place with a speed of 65 km/hr at
an interval of 15 minutes. A man coming from the opposite direction towards the place meets the cars at an interval of 13 minutes. What is the speed of the man?Solution
Distance covered in 15 minutes at 65 km/hr = 65 x (15/60) Distance covered in 13 minutes at (65 + x) km/hr = (13/60) x (65 + x) Now, Distance covered in 15 minutes at 65 km/hr = Distance covered in 13 minutes at (65 + x) km/hr ⇒ 65 x (15/60) = (13/60) x (65 + x) ⇒ 65 x 15 = 845 + 13x ⇒ 975 = 845 + 13x ⇒ 13x = 975 - 845 = 130 ⇒ x = 10 km/hr
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
What approximate value should come in the place of question mark in the following questions?
25.02% of 460.02 + ?% of 300.02 = 295.21
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
26.23 × 31.82 + 44.8% of 1200 + ? = 1520
66.05 × 17.95 – 38.99 × 18.12 = (60 + ?) × 6
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, find the value of (4A - B) .
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