Question
A train started from station P and preceded towards
station Q at a speed of 98 km/h. 30 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 643 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 98 x 30/60 km Distance travelled by train started from station Q = (98 + 100) x t km Total distance between station P and Q = 643 km Now, 98 x (30/60) + (98 + 100) x t = 643 ⇒ 49 + 198t = 643 ⇒ 198t = 643 – 49 = 594 ⇒ t = 594/198 = 3 hours Distance travelled by train starting from station P at all meeting point = 49 + 98 x 3 = 343 km
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