A train started from station P and preceded towards station Q at a speed of 72 km/h. 45 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 398 km, at what distance from station P will the trains meet?
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 72 x 45/60 km Distance travelled by train started from station Q = (72 + 100) x t km Total distance between station P and Q = 398 km Now, 72 x (45/60) + (72 + 100) x t = 398 ⇒ 54 + 172t = 398 ⇒ 172t = 398 – 54 = 344 ⇒ t = 344/172 = 2 hours Distance travelled by train starting from station P at all meeting point = 54 + 72 x 2 = 198 km
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