Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 72 x 45/60 km Distance travelled by train started from station Q = (72 + 100) x t km Total distance between station P and Q = 398 km Now, 72 x (45/60) + (72 + 100) x t = 398 ⇒ 54 + 172t = 398 ⇒ 172t = 398 – 54 = 344 ⇒ t = 344/172 = 2 hours Distance travelled by train starting from station P at all meeting point = 54 + 72 x 2 = 198 km
? = 41.92% of 49.96% of (45.07 1.97 – 4.98 2.03 )
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
509.85 ÷ 15.05 + 210.16 – 18.06 × 5.95 = ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
9.99% of 19.86% of 30.23% of (11999.84 × 9.68) = ?
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
(3/8) × 479.84 + (2/5) × 449.67 = ? × 12.25
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
