Question
Train 'R' starts from Lucknow to Kanpur at 5:00 a.m. Train
'S' starts from Kanpur to Lucknow at 7:00 a.m., traveling at 50 km/h. They cross each other at 12:00 noon. The distance between the cities is 550 km. Find the speed of train 'R'.Solution
ATQ,
Let the speed of train 'R' be 'x' km/h
Distance covered alone = 2 × x = 2x
Time together = 5 hours
ATQ;
5 × (50 + x) = 550 - 2x
Or, 250 + 5x = 550 - 2x
Or, 300 = 7x
So, x = 42.86
So, speed of train 'R' = 42.86 km/h
More Trains Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√323.89  × (3.20) ÷ 9.02 =?
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
 5983.987 + 59832.999 – 598.873 = ?
(100.01% of 44.89) ÷ 14.98 = √? - √48.98
(5.013 – 30.04) = ? + 11.98% of 4799.98
(4096)1/3 × 10.11 × 11.97 ÷ 24.32 = ? + 15.022
- √81.45 + √225.60 + 49.89% of (520.43 + 22.13% of 131.45) = ?
40.024 of 54.89% of 19.9 = ? × √(2661.98/22.09)Â
Find the approximate value of Question mark(?) for given equation.Â
135.86% of 249.99 + 24.95 × 14.03 ÷ 2.01 = ?
