Question
How many seconds will a train 68 m in length, travelling
at the rate of 40 km an hour, take to pass another train 92 m long, proceeding in the same direction at the rate of 28 km an hour?Solution
Relative speed = 40 – 28 = 12 km/hr Speed (m/sec) = 12 × (5/18) = 10/3 m/sec Time = Total length of both the trains/Relative speed => Time = (92 + 68)/(10/3) = 48 sec
Solve for x in the equation: 3(x + 2) + 2(2x - 5) = 5x + 9
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